concentration_calculations
Concentration calculations
60 mg of Iron nitrate is (0.06 g)/(404 g/mol)=0.15 mmol
0.15 mmol/45 ml = 3 mmol/l = 3 mM.
concentration_calculations.txt · Last modified: 2019/09/09 20:33 by ethanminot
60 mg of Iron nitrate is (0.06 g)/(404 g/mol)=0.15 mmol
0.15 mmol/45 ml = 3 mmol/l = 3 mM.